8x^2+5x+4=2x^2-5x-8

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Solution for 8x^2+5x+4=2x^2-5x-8 equation: 



8x^2+5x+4=2x^2-5x-8

We move all terms to the left:

8x^2+5x+4-(2x^2-5x-8)=0

We get rid of parentheses

8x^2-2x^2+5x+5x+8+4=0

We add all the numbers together, and all the variables

6x^2+10x+12=0

a = 6; b = 10; c = +12;
Δ = b2-4ac
Δ = 102-4·6·12
Δ = -188
Delta is less than zero, so there is no solution for the equation

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